简单C语言—随机数的产生
admin 于 2012年11月03日 发表在 C/C++开发笔记
下面程序是模拟投掷骰子的程序,输入投掷的总次数,会显示从1-6不同的点数出现的不同次数,而且数字全为随机的,什么意思呢?就是说:你每次输入即使是相同的投掷次数,显示1-6出现的次数都可能是不相同,其实就是电玩游戏的一个缩影
源码:点击下载附件
/* Fig. 5.8: fig_08.c */ #include <stdio.h> #include <stdlib.h> /* function main begins */ int main( void ) { int frequency1 = 0; int frequency2 = 0; int frequency3 = 0; int frequency4 = 0; int frequency5 = 0; int frequency6 = 0; int i; int roll; /* roll counter, value 1 to i */ int face; printf( "Input the i's number: " ); scanf( "%d", &i ); srand( time( NULL ) ); /* *************************** */ /* loop i times and output results */ for ( roll = 1; roll <= i; roll++ ){ face = 1 + rand() % 6; switch ( face ){ case 1: ++frequency1; break; case 2: ++frequency2; break; case 3: ++frequency3; break; case 4: ++frequency4; break; case 5: ++frequency5; break; case 6: ++frequency6; break; } /*end swith*/ } /* display the results */ printf( "%s%13s\n", "face", "Frequency" ); printf( " 1%13d\n", frequency1 ); printf( " 2%13d\n", frequency2 ); printf( " 3%13d\n", frequency3 ); printf( " 4%13d\n", frequency4 ); printf( " 5%13d\n", frequency5 ); printf( " 6%13d\n", frequency6 ); return 0; /* successful terminnation */ } /* end main */
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标签:C/C++